**Question 1: **Compute the set { 6, 8, 9, 7, 2, 5, 4 }

** Solution: **
- Arrange the given data 2, 4, 5, 6, 7, 8, 9
- The minimum and maximum values are 2 and 9 respectively for the above problem.
- From the given data we see that median is 6.
- The lower half is {2, 4, 5} and the middle term of that half is 4. Therefore, the lower quartile is
**4.** - The upper half is {7, 8, 9}, and the middle term of that half is 8. Therefore, the upper quartile is
**8.**

**Question 2: **Suppose we wish to compute the five number summary for the set {11, 25, 29, 43, 56, 68, 72, 87, 92, 104}

** Solution: **
- Here the given data is already ordered { 11, 25, 29, 43, 56, 68, 72, 87, 92, 104 } so the minimum and maximum values are 11 & 104 respectively.
- The median is $\frac{56+68}{2}$ = 62, as 56 and 68 represents the middle values.
- Total number of observations for the given problem is 10, as (10 -1 = 9)
is not evenly divisible by four, so the upper quartile is the median of
the observations to the right of 62, therefore the upper half is {68, 72, 87, 92, 104} and the median for this set is 87. Now the upper quartile for the above problem (Q3) is 87.
- So now the lower quartile is the median of the observations to the left of 62, therefore the lower half is { 11, 25, 29, 43, 56 } and the median for this set is 29. Now the lower quartile for the above problem (Q1) is 29.