With regard to solving the factorial problems, the given factorials inside the problem should be expanded with the formula of the factorial.

**For Illustration:** if we are asked to search for the value of n!, then we should write the quantity n itself. Put a multiplication sign next and write several 1 less as compared to n, i. e. (n - 1). Again put a multiplication sign and write several 1 less as compared to (n - 1), when i. e. (n - 2).

Continue the procedure until reaching in 1. At the finish, the product of all numbers is to be calculated.

There could possibly be problems where numerator in addition to denominator both comprise factorial. In this kind of problems, the whole expansions on the factorials is not necessary to be multiplied. In reality, many of this terms do get cancelled out. We have to just multiply simply remaining terms.

**Down below, there is a listing of few factorials. Have a look at them!**

0! = 1

1! = 1

2! = 2. 1 = 2

3! = 3 . 2. 1 = 6

4! = 4 . 3 . 2 . 1 = 24

5! = 5 . 4 . 3 . 2 . 1 = 120

6! = 6 . 5 . 4 . 3 . 2 . 1 = 720

7! = 7 . 6 . 5 . 4 . 3 . 2 . 1 = 5040

and so on.