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A Kite is a quadrilateral with two distinct pairs of adjacent sides which are equal. A Kite has two pairs of equal sides in which each pair must be distinct disjoint and must be adjacent to each other, sharing a common vertex. This means, the pairs cannot have a side in common. Only one pair of angle which is the angle between the unequal sides is equal to its opposite angle. The diagonal are perpendicular to each other and longer diagonal bisects the shorter one. |
- The angles between the unequal sides and opposite to each other are equal.
- The diagonals of a kite are perpendicular to each other.
- The diagonal of a kite which is longer bisects the diagonal which is shorter.
- One diagonal divides the quadrilateral into two congruent triangles and so becomes the line of symmetry.
- One diagonal bisects a pair of opposite angles which are unequal.
Solved Examples
Given that AB = 3cm and AD = 7 cm.
Solution:
The length of one side, AB = 3cm. This is equal to the length of BC as the sides AB and BC are equal.
The length of another side, AD = 7 cm. This is equal to the length of CD as the sides AD and CD are equal.
Perimeter of a Kite = 2a + 2b, where a = AB and b = AD are the lengths of each side in each pair of equal sides.
= 2(3) + 2(7).
= 6 + 14.
Perimeter of the given kite = 20 cm.
Solution:
Given $d_1$ = 3cm and $d_2$ = 6cm.
Area of Kite = $\frac{d_1 d_2}{2}$ where $d_1$ and $d_2$ are the lengths of the diagonals.
Area of the given kite = $\frac{(3 \times 6)}{2}$ = $\frac{18}{2}$ = 9 sq.cm.
Solution:
Given $d_1$ = 16cm and area of the kite = 176 sq.cm.
Area of Kite = $\frac{d_1 d_2}{2}$ where $d_1$ and $d_2$ are the lengths of the diagonals.
Diagonal $d_2$ = $\frac{(Area \times 2)}{d_1}$ = $\frac{176 \times 2}{16}$ = 11 $\times$ 2 = 22 cm.
Solution:
Let the two unequal sides of a kite be a and b. Then we have b = 7a – 5.
Perimeter of a Kite = 2a + 2b, where a and b are the lengths of each side in each pair of equal sides.
The Perimeter of the given kite = 86 cm.
Thus, 86 = 2a + 2(7a - 5)
86 = 2a + 14a - 10 = 16a - 10.
16a = 96
a = $\frac{96}{16}$ = 6 cm.
b = 7a – 5 = 7(6) – 5 = 42 – 5 – 37 cms.
The length of each side of the kite is 6 cm, 6 cm, 37cm and 37 cm.
Solution:
| Statements | Reasons |
|---|---|
| 1. AD ≅ CD | 1. Given. |
| 2. ∠CDB ≅ ∠ADB | 2.Given. |
| 3. BD ≅ BD | 3.Reflexive Property. |
| 4. ΔBCD ≅ Δ BAD | 4.By SAS postulate. |
| 5. BC ≅BA | 5.By CPCTC. |
| 6. ABCD is a Kite | 6.If a quadrilateral has two disjoint adjacent sides that are congruent, then the quadrilateral is a kite. |
