Let us look at some examples to understand the concepts better.

**Example 1:**

Find the area of the figure given below

**Solution:**

We know that area of a rectangle is the product of its two consecutive sides. There are two ways of solving the given problem.

**First Way:**

Complete the whole rectangle. Find the area of complete rectangle and the smaller rectangle. Subtract the two to get the actual area

Area of full rectangle = 6 $\times$ (4 + 3) = 6 $\times$ 7 = 42 sq cm

Area of small cut out rectangle = 2 $\times$ 3 = 6 sq cm.

Required area = 42 – 6 = 36 sq cm.

**Second Way:**

The second method is to break the rectangle in two rectangles from the line of disconnection and then find the individual areas of the two rectangles. Finally add them to obtain the required area.

Area of bigger rectangle = (6 – 2) $\times$ (4 + 3) = 4 $\times$ 7 = 28 sq cm

Area of smaller rectangle = 2 $\times$ 4 = 8 sq cm

Required area = 28 + 8 = 36 sq cm

It can be seen that in both the cases the answer is the same which implies that both the methods are correct.

**Example 2:**

Find the perimeter of the shape below

**Solution:**

Here two sides are missing. Let us first determine that.

x = 10 – 4 – 5 = 1 ft

y = 8 – 1 – 2 = 5 ft

We know that perimeter is sum of all sides of the shape.

Perimeter = 10 + 5 + 5 + 2 + 1 + 1 + 4 + 8 = 36 ft.

So, once the concepts are clear and we know the formulas for all basic regular or standard shapes then given any type of problem n irregular shapes, we can solve it accurately without any hesitation.