Solve y = $x^{2}$ - 3x - 10 by graphing and find x.

Step - 1 : Assigning the variables a = 1, b = -3, c = 10

Step - 2 : As a > 0, the graph of the given equation is a parabola with a minimum point and opens upwards.

Step - 3 : Find vertex:

x =

$\frac{-b}{2a}$x =

$\frac{-(-3)}{2(1)}$x =

$\frac{3}{2}$ $\Rightarrow$ 1.5

So y = $(1.5)^{2}$ - 3(1.5) - 10

y = -12.25

The Minimum point is (1.5, -12.25)

Step - 4 : To find y-intercept substitute x = 0 in the given equation

y = $(0)^{2}$ - 3(0) -10 = -10

(0, -10) is the y-intercept.

Step - 5 : Substitute y = 0 in the given equation and solve

$x^{2}$ - 3x -10

Factorize: $x^{2}$ - 3x - 10

$x^{2}$ + 2x - 5x -10 = 0

x(x + 2) - 5(x + 2) = 0

(x + 2)(x - 5) = 0

=> x = 5, x = -2

The graph is given below :

From the graph we can see that the values are (-2, 0) and (5, 0) respectively .