Any of the following methods can be used to obtain points that satisfy a linear equation whose graph is an straight line.

**Intercept method:** Determine from the linear equation the point at which the line crosses the x-axis by letting y = 0 and solving for x, and the point at which the line crosses the y-axis by letting x = 0 and solving for y. This method can be used only for oblique lines that do not pass through the origin. Example: The graph of the equation $2x + 3y = 6$ crosses the x-axis at (3,0), and the y-axis at (0,2).**Slope-Intercept method: **Put the equation in $y = mx+b$ form. Graph (0,b), the point at which the line crosses the y-axis. Use the slope to locate at least one additional point.**Three-point method:** Solve the given equation for y, if necessary. Determine the coordinate of three points on the line by replacing x with three convenient values and then determining the corresponding values of y.